gibson:teaching:fall-2013:math445:lab11
====== Differences ====== This shows you the differences between two versions of the page.
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gibson:teaching:fall-2013:math445:lab11 [2013/12/05 08:55] szeto |
gibson:teaching:fall-2013:math445:lab11 [2013/12/05 09:10] (current) szeto |
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| [t,x]= ode45(f,[0:0.1:200] ,[ 0,0,v0*cos(theta), v0*sin(theta) ); | [t,x]= ode45(f,[0:0.1:200] ,[ 0,0,v0*cos(theta), v0*sin(theta) ); | ||
| - | xdistance = interp1(x(50:end,2), x(50:end,1), 0); % This is how you can compute ''xdistance'' accurately from an ''x,y'' trajectory % using interpolation. It will return the value of $x$ for which $y=0$, i.e. where the cannonball hits the ground. | + | |
| + | xdistance = interp1(x(50:end,2), x(50:end,1), 0); % This is how you can compute ''xdistance'' | ||
| + | % accurately from an ''x,y'' trajectory using interpolation. | ||
| + | % It will return the value of $x$ for which $y=0$, i.e. | ||
| + | % where the cannonball hits the ground. | ||
| end | end | ||
| </code> | </code> | ||
| - | Now on the command line, you can USE this function like this. | + | Once your function works, play around with the parameters ''v0, theta'' to answer the questions. |
| + | On the command line, you can USE this function like this. | ||
| <code> | <code> | ||
| xdistance = projectile(100,pi/2) | xdistance = projectile(100,pi/2) | ||
| Line 62: | Line 68: | ||
| - | + | If your xdistance is a NaN, you may have to increase the number 50 in the interp1 function (1000 might be good, that is roughly half the length of [0:0.1:200]). | |
| - | That will return the value of $x$ for which $y=0$, i.e. where the cannonball hits the ground. Once your function works, play around with the parameters ''v0, theta'' to answer the questions. If your xdistance is a NaN, you may have to increase the time span that you're running ode45 on. | + | |
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gibson/teaching/fall-2013/math445/lab11.1386262528.txt.gz · Last modified: 2013/12/05 08:55 by szeto
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